For more CA foundation questions on differential calculus Visit www.gneet.com
EXERCISE 8 A Q.16
Q.16) Given x = at2, y = 2at; then dy/dx is calculated as
Try again
Try again
CORRECT
Try again
x= a t2
Diff.w.r.t.t, we get
dx/dt = 2at . --------(1)
now y = 2at
Diff.w.r.t.t, we get dy/dt = 2a ---(2)
Now, dy/dx = (dy/dt)/(dx/dt)
∴ dy/dx = 2a/2at = 1/t